LeetCode Question - 128. Longest Consecutive Sequence πŸƒπŸ»

LeetCode Question - 128. Longest Consecutive Sequence πŸƒπŸ»

5th July 2022 | πŸ—“ Daily LeetCode Challenge - #5


2 min read

About the Series

Problem-solving is a key skill set for any tech-related stuff you might be working on.

When it comes to developers it's one of the most crucial skills which is needed in almost any day-to-day code you might be writing.

So, this series of blogs is all about practicing Daily LeetCode Challenges & Problem-solving. πŸš€

Problem Statement

Longest Consecutive Sequence

Given an unsorted array of integers nums, return the length of the longest consecutive elements sequence.

You must write an algorithm that runs in O(n) time.

Example 1:

Input: nums = [100,4,200,1,3,2]
Output: 4
Explanation: The longest consecutive elements sequence is [1, 2, 3, 4]. Therefore its length is 4.

Example 2:

Input: nums = [0,3,7,2,5,8,4,6,0,1]
Output: 9

Video Explanation




  1. we create a numsMap and store all the values in the map.
  2. Now Iterate through the nums array and check if it is the starting point of a consecutive sequence of values or not. ie. num-1 exists or not. If it doesn’t exist that means it can be starting value of the sequence.
  3. Now check whether the next consecutive value exists or not in a while loop and increment the value of the current sequence length.
  4. Compare the longest sequence length with the current sequence length whichever is maximum will be stored in longest sequence length
  5. Finally return the longest sequence length.

Code in JS πŸ§‘β€πŸ’»

 * @param {number[]} nums
 * @return {number}
var longestConsecutive = function (nums) {
  var numsMap = new Map();
  for (const num of nums) {

  var longestSequence = 0;
  for (const num of nums) {
    if (!numsMap.has(num - 1)) {
      var currentSequence = 1;
      var currentNum = num;
      while (numsMap.has(currentNum + 1)) {
      longestSequence = Math.max(longestSequence, currentSequence);
  return longestSequence;

Time Complexity : O(n)

Space Complexity: O(1)

Similar Questions for practice

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